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Question
Evaluate the determinant.
`|(3,-1,-2),(0,0,-1),(3,-5,0)|`
Evaluate
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Solution
`|(3,-1,-2),(0,0,-1),(3,-5,0)|`
= `3|(0,-1),(-5,0)| + 1|(0,-1),(3,0)| - 2|(0,0),(3,-5)|`
= 3[0 × 0 − (−1) × (−5)] + 1[0 × 0 − (−1) × 3] − 2[0 × (−5) − 0 × (3)]
= 3[0 − 5] + 1[0 + 3] − 2[0 − 0]
= 3 × (−5) + 1 × (3) − 2 × 0
= −15 + 3
= −12
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