Let log5 1 = x⇒ 5x = 1⇒ 5x = 50⇒ x = 0Thus, log5 1 = 0

Evaluate : Log5 1 | Shaalaa.com

Evaluate : log₅ 1

Sum

Let log₅ 1 = x
⇒ 5^x = 1
⇒ 5^x = 5⁰
⇒ x = 0
Thus, log₅ 1 = 0

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Interchanging Logarithmic and Exponential Forms

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Chapter 8: Logarithms - Exercise 8 (A) [Page 104]

Chapter 8 Logarithms
Exercise 8 (A) | Q 7.3 | Page 104

Express the following in exponential form :
log₁₀0.01 = - 2

Find the logarithm of : 32 to the base 4

Find the logarithm of : `1/16` to the base 4

Find the logarithm of : `1/81` to the base 27

State, true or false : If log₁₀ x = a, then 10^x = a.

Find x, if : log_x 2 = - 1.

Find x, if : log₅ (x - 7) = 1

If log_am = n, express a^{n - 1} in terms of a and m.

Given log₅y = n. Express 5^{3n + 2} in terms of y.

State true or false in the following:
If log ₂ 8 = 3, then log ₈ 2 = `(1)/(3)`

Evaluate : Log5 1