Advertisements
Advertisements
Question
Evaluate : log5 125
Sum
Advertisements
Solution
Let log5 125 = x
⇒ 5x = 125
⇒ 5x = 5 x 5 x 5
⇒ 5x = 53
⇒ x = 3
Thus, log5125 = 3
shaalaa.com
Interchanging Logarithmic and Exponential Forms
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Find the logarithm of : 0.001 to the base 10
Find the logarithm of : 32 to the base 4
Find the logarithm of : 0.125 to the base 2
State, true or false : If log10 x = a, then 10x = a.
Find x, if : logx 2 = - 1.
Find x, if : log7 (2x2 - 1) = 2
Evaluate : log10 0.01
Evaluate : log2 ( 1 ÷ 8 )
Given log2 x = m. Express 2m - 3 in terms of x.
If log2x = a and log3 y = a, write 72a in terms of x and y.
