Advertisements
Advertisements
Question
Evaluate:
`(3sin72^@)/(cos18^@) - sec32^@/(cosec58^@)`
Advertisements
Solution
`(3sin72^@)/(cos18^@) - sec32^@/(cosec58^@)`
= `(3sin(90^@ - 18^@))/(cos18^@) - (sec(90^@ - 58^@))/(cosec58^@)`
= `(3cos18^@)/(cos18^@) - (cosec58^@)/(cosec58^@)`
= 3 – 1
= 2
RELATED QUESTIONS
If the angle θ= –60º, find the value of cosθ.
if `cos theta = 4/5` find all other trigonometric ratios of angles θ
If `tan theta = 12/5` find the value of `(1 + sin theta)/(1 -sin theta)`
If `sqrt3 tan theta = 3 sin theta`, find the value of `sin^2 theta - cos^2 theta`
Find the value of x, if cos x = cos 60° cos 30° – sin 60° sin 30°
Prove that:
`(cos(90^circ - theta)costheta)/cottheta = 1 - cos^2theta`
Use tables to find sine of 21°
If θ is an acute angle such that sec2 θ = 3, then the value of \[\frac{\tan^2 \theta - {cosec}^2 \theta}{\tan^2 \theta + {cosec}^2 \theta}\]
A, B and C are interior angles of a triangle ABC. Show that
sin `(("B"+"C")/2) = cos "A"/2`
If y sin 45° cos 45° = tan2 45° – cos2 30°, then y = ______.
