Advertisements
Advertisements
प्रश्न
Evaluate:
`(3sin72^@)/(cos18^@) - sec32^@/(cosec58^@)`
Advertisements
उत्तर
`(3sin72^@)/(cos18^@) - sec32^@/(cosec58^@)`
= `(3sin(90^@ - 18^@))/(cos18^@) - (sec(90^@ - 58^@))/(cosec58^@)`
= `(3cos18^@)/(cos18^@) - (cosec58^@)/(cosec58^@)`
= 3 – 1
= 2
APPEARS IN
संबंधित प्रश्न
if `cosec A = sqrt2` find the value of `(2 sin^2 A + 3 cot^2 A)/(4(tan^2 A - cos^2 A))`
Solve.
sin42° sin48° - cos42° cos48°
Evaluate.
`(cos^2 32^@+cos^2 58^@)/(sin^2 59^@+sin^2 31^@)`
Evaluate:
`(sin35^circ cos55^circ + cos35^circ sin55^circ)/(cosec^2 10^circ - tan^2 80^circ)`
Use tables to find the acute angle θ, if the value of cos θ is 0.9848
Evaluate:
`(5sin66^@)/(cos24^@) - (2cot85^@)/(tan5^@)`
If the angle θ = –45° , find the value of tan θ.
If 5θ and 4θ are acute angles satisfying sin 5θ = cos 4θ, then 2 sin 3θ −\[\sqrt{3} \tan 3\theta\] is equal to
If sec A + tan A = x, then sec A = ______.
If x tan 60° cos 60°= sin 60° cot 60°, then x = ______.
