Advertisements
Advertisements
Question
Evaluate:
Advertisements
Solution
100 and 270 are not perfect cubes; therefore, we use the following property:
\[\therefore \sqrt[3]{100} \times \sqrt[3]{270}\]
\[ = \sqrt[3]{100 \times 270}\]
\[= \sqrt[3]{\left\{ 2 \times 2 \times 2 \right\} \times \left\{ 3 \times 3 \times 3 \right\} \times \left\{ 5 \times 5 \times 5 \right\}}\]
\[ = 2 \times 3 \times 5\]
\[ = 30\]
Thus, the answer is 30.
APPEARS IN
RELATED QUESTIONS
Find the cube root of the following numbers by the prime factorisation method.
27000
Find the cube root of the following number by the prime factorisation method.
175616
Find the cube root of the following number by the prime factorisation method.
91125
\[\sqrt[3]{} . . . = \sqrt[3]{7} \times \sqrt[3]{8}\]
Making use of the cube root table, find the cube root
9800 .
Find the cube root of 216.
Find the cube root of -1331.
The cube root of 0.000004913 is ___________
The least number by which 72 be divided to make it a perfect cube is ______.
Using prime factorisation, find the cube roots of 2197
