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Evaluate: ∫13cos(logx)x dx

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Question

Evaluate: `int_1^3 (cos(logx))/x  "d"x`

Sum
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Solution

Let I = `int_1^3 (cos(log x))/x  "d"x`

Put log x = t

∴ `1/x  "d"x` = dt

When x = 1, t = log 1 = 0 and when x = 3, t = log 3

∴ I = `int_0^log3  cos "t"  "dt"`

= `[sin  "t"]_0^log3`

= sin (log 3) − sin 0

= sin (log 3)

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Methods of Evaluation and Properties of Definite Integral
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Chapter 2.4: Definite Integration - Short Answers I

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