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Evaluate: ∫0111+x2 dx

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Question

Evaluate: `int_0^1 1/(1 + x^2)  "d"x`

Sum
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Solution

`int_0^1 1/(1 + x^2)  "d"x = [tan^-1 x]_0^1`

= tan–11 – tan–1

= `pi/4 - 0`

= `pi/4`

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Methods of Evaluation and Properties of Definite Integral
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Chapter 2.4: Definite Integration - Very Short Answers

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