Question

Evaluate :
`[1.2 xx 1.2 + 1.2 xx 0.3 + 0.3 xx 0.3 ]/[ 1.2 xx 1.2 xx 1.2 -  0.3 xx 0.3 xx 0.3]`

Answer 1

`[1.2 xx 1.2 + 1.2 xx 0.3 + 0.3 xx 0.3 ]/[ 1.2 xx 1.2 xx 1.2 -  0.3 xx 0.3 xx 0.3]`

Let 1.2 = a and 0.3 = b
Then, the given expression becomes
`[ a xx a + a + b + b xx b]/[a xx a xx a - b xx b xx b]`

= `[a^2 + ab + b^2 ]/[ a^3 - b^3 ]`

= `[a^2 + ab + b^2]/[( a - b )( a^2 + ab + b^2 )]`

= `1/[a - b]`

= `1/[1.2 - 0.3]`

= `1/0.9`

= `10/9`

= `1 1/9`