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प्रश्न
Evaluate :
`[1.2 xx 1.2 + 1.2 xx 0.3 + 0.3 xx 0.3 ]/[ 1.2 xx 1.2 xx 1.2 - 0.3 xx 0.3 xx 0.3]`
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उत्तर
`[1.2 xx 1.2 + 1.2 xx 0.3 + 0.3 xx 0.3 ]/[ 1.2 xx 1.2 xx 1.2 - 0.3 xx 0.3 xx 0.3]`
Let 1.2 = a and 0.3 = b
Then, the given expression becomes
`[ a xx a + a + b + b xx b]/[a xx a xx a - b xx b xx b]`
= `[a^2 + ab + b^2 ]/[ a^3 - b^3 ]`
= `[a^2 + ab + b^2]/[( a - b )( a^2 + ab + b^2 )]`
= `1/[a - b]`
= `1/[1.2 - 0.3]`
= `1/0.9`
= `10/9`
= `1 1/9`
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