Advertisements
Advertisements
Question
Evaluate.
`(1/2)^(-5)`
Evaluate
Advertisements
Solution
`(1/2)^(-5) = (2/1)^5` ...`[∵ (1/b)^-m = (b/a)^m]`
= `(2 xx2 xx 2xx2xx 2)/(1 xx 1xx 1xx 1xx1)`
= `32/1`
= 32
shaalaa.com
Is there an error in this question or solution?
Chapter 10: Exponents and Powers - EXERCISE 10.1 [Page 125]
APPEARS IN
RELATED QUESTIONS
Evaluate.
(−4)−2
Express the following as a rational number of the form \[\frac{p}{q},\] where p and q are integers and q ≠ 0.
\[\frac{1}{3^{- 2}}\]
Simplify:
\[\left( 3^{- 1} \times 4^{- 1} \right)^{- 1} \times 5^{- 1}\]
Simplify:
\[\left\{ \left( \frac{1}{3} \right)^{- 3} - \left( \frac{1}{2} \right)^{- 3} \right\} \div \left( \frac{1}{4} \right)^{- 3}\]
Simplify:
\[\left[ \left\{ \left( \frac{- 1}{4} \right)^2 \right\}^{- 2} \right]^{- 1}\]
By what number should \[\left( \frac{1}{2} \right)^{- 1}\] be multiplied so that the product may be equal to \[\left( \frac{- 4}{7} \right)^{- 1} ?\]
Find x, if
\[\left( \frac{2}{5} \right)^{- 3} \times \left( \frac{2}{5} \right)^{15} = \left( \frac{2}{5} \right)^{2 + 3x}\]
Square of \[\left( \frac{- 2}{3} \right)\] is
\[\left( \frac{- 2}{5} \right)^7 \div \left( \frac{- 2}{5} \right)^5\] is equal to
The cells of a bacteria double itself every hour. How many cells will there be after 8 hours, if initially we start with 1 cell. Express the answer in powers.
