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Equilibrium constant of the reaction, 2CuA⊕A(aq)⟶CuA2⊕A(aq)+CuA(s) is 1.2 × 106. What is the standard potential of the cell in which the reaction takes place?

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Question

Equilibrium constant of the reaction, \[\ce{2Cu^{\oplus}_{(aq)} -> Cu^{2\oplus}_{(aq)} + Cu_{(s)}}\] is 1.2 × 106. What is the standard potential of the cell in which the reaction takes place?

Numerical
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Solution

Given: Equilibrium constant of the reaction (K) = 1.2 × 106.

To find: Standard potential of cell \[\ce{E^{\circ}_{cell}}\]

Formulae: \[\ce{E^{\circ}_{cell}}\] = `(0.0592  "V")/"n" log_10K`

Calculation:

For the given reaction, n = 1.

Using formula,

`("E"_"cell"^circ) = 0.0592/1 xx log_10 (1.2 xx 10^6)`

`("E"_"cell"^circ) = 0.0592 xx (6.079)` = 0.36 V

The standard cell potential of cell is 0.36 V.

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Chapter 5: Electrochemistry - Exercises [Page 118]

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Balbharati Chemistry [English] Standard 12 Maharashtra State Board
Chapter 5 Electrochemistry
Exercises | Q 4.04 | Page 118

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