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For a relation: Δ_rG = −nFE_cell \\ce{E_{cell} = E^\circ_{cell}}\ in which of the following conditions?

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Question

For a relation:

ΔrG = −nFEcell

\[\ce{E_{cell} = E^\circ_{cell}}\] in which of the following conditions?

Options

  • The concentration of any one of the reacting species should be unity.

  • The concentration of all the product species should be unity.

  • The concentration of all the reacting species should be unity.

  • The concentration of all reacting and product species should be unity.

MCQ
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Solution

The concentration of all reacting and product species should be unity.

Explanation:

When the concentration of all reacting and product species is kept at unity, then \[\ce{E_{cell} = E^\circ_{cell}}\] and the given relation will become `Δ_rG = -nFE_(cell)^\circ`.

E.g., redox reaction for a Daniell cell:

\[\ce{Zn_{(s)} + Cu^{2+}_{ (aq)} -> Zn^{2+}_{ (aq)} + Cu_{(s)}}\]

Solutions of CuSO4 and ZnSO4 are the reacting species.

The Ecell for this cell: \[\ce{E_{cell} = E^\circ_{cell}}\]

`-(RT)/(nF) ln  ([Zn^(2+)])/([Cu^(2+)])`

Ecell = Ecell

if [Zn2+] = [Cu2+] = 1

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