English
Karnataka Board PUCPUC Science Class 11

Elements X,Y and Z have 4, 5 and 7 valence electrons respectively. Write the molecular formula of the compounds formed by these elements individually with hydrogen.

Advertisements
Advertisements

Question

Elements \[\ce{X, Y}\] and \[\ce{Z}\] have 4, 5 and 7 valence electrons respectively. Write the molecular formula of the compounds formed by these elements individually with hydrogen.

Short/Brief Note
Advertisements

Solution

To the electronic configuration, a total of 8 electrons must be present in the valence shell of an element. Element \[\ce{X}\] has 4 valence electrons, so it will share the remaining 4 electrons for the formation of the bond, the molecular formula will be \[\ce{XH4}\]. The element \[\ce{Y}\] has 5 valence shell electrons, so it will form 3 bonds and the formula will be \[\ce{YH3}\]. The element \[\ce{Z}\] has 7 valence shell electrons, so it will form one bond with hydrogen and has the molecular formula \[\ce{H - Z}\].

shaalaa.com
  Is there an error in this question or solution?
Chapter 4: Chemical Bonding and Molecular Structure - Multiple Choice Questions (Type - I) [Page 46]

APPEARS IN

NCERT Exemplar Chemistry Exemplar [English] Class 11
Chapter 4 Chemical Bonding and Molecular Structure
Multiple Choice Questions (Type - I) | Q 47.(i) | Page 46

RELATED QUESTIONS

Discuss the shape of the following molecules using the VSEPR model:

BeCl2, BCl3, SiCl4, AsF5, H2S, PH3


Although geometries of NH3 and H2O molecules are distorted tetrahedral, bond angle in water is less than that of ammonia. Discuss.


Select and write the most appropriate alternatives from the given choices.

Valence Shell Electron Pair repulsion (VSEPR) theory is used to predict which of the following:


According to VSEPR theory, the repulsion between different parts of electrons obey the order.


Shape of ClF3 is ______.


Explain VSEPR theory. Applying this theory to predict the shapes of IF7 and SF6.


The H-N-H bond angle in NH3 molecule is ____________.


Explain the non-linear shape of \[\ce{H2S}\] and non-planar shape of \[\ce{PCl3}\] using valence shell electron pair repulsion theory.


Elements \[\ce{X, Y}\] and \[\ce{Z}\] have 4, 5 and 7 valence electrons respectively. Which of these compounds will have the highest dipole moment?


Which of the possible molecule/species is having maximum values for dipole moment. (where "A" is the central atom)?


Consider the species CH4, `"NH"_4^+` and `"BH"_4^-`. Choose the correct option with respect to these species.


Number of lone pair(s) of electrons on central atom and the shape of BrF3 molecule respectively are ______.


The number of lone pairs of electrons on the central I atom in `"I"_3^-` is ______.


In the following structure, the percentage of the 's' character in the lone pair occupy by the oxygen atom is ______.

Given: Cos θ = −0.99


What is the geometry of a water molecule?


Which of the following molecules have regular geometry without lone pair of electrons in the valence shell of central atom?


Match List-I with List-II.

  List-I   List-II
A. XeO3 I. sp3d; linear
B. XeF2 II. sp3; pyramidal
C. XeOF4 III. sp3d3; distorted octahedral
D. XeF6 IV. sp3d2; square pyramidal

Choose the correct answer from the options given below:


Match List-I with List-II:

List-I
(Compound)
List-II
(Shape/Geometry)
A. NH3 I. Trigonal pyramidal
B. BrF5 II. Square planar
C. XeF4 III. Octahedral
D. SF6 IV. Square pyramidal

Choose the correct answer from the options given below:


In XeF2, XeF4, XeF6 the number of lone pairs on Xe are respectively ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×