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During discharging of a cell, how does terminal voltage (V) compare to EMF (ε)?

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Question

During discharging of a cell, how does terminal voltage (V) compare to EMF (ε)?

Options

  • V > ε

  • V = ε

  • V < ε

  • V = ε/2

MCQ
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Solution

During discharge, current flows from the cell, causing a voltage drop across the internal resistance. Using the formula \[V = ε - Ir\], since the term \[Ir\] is positive and subtracted from ε, the terminal voltage is always less than the EMF during discharge. This voltage drop increases with higher current.

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