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Question
During discharging of a cell, how does terminal voltage (V) compare to EMF (ε)?
Options
V > ε
V = ε
V < ε
V = ε/2
MCQ
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Solution
During discharge, current flows from the cell, causing a voltage drop across the internal resistance. Using the formula \[V = ε - Ir\], since the term \[Ir\] is positive and subtracted from ε, the terminal voltage is always less than the EMF during discharge. This voltage drop increases with higher current.
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