Advertisements
Advertisements
Questions
Draw two structural isomers of butane.
Draw structural isomers of butane (C4H10).
Chemical Equations/Structures
Advertisements
Solution 1
The two isomers of butane, C4H10 are:
\[\begin{array}{cc}
\ce{H}\phantom{....}\ce{H}\phantom{....}\ce{H}\phantom{....}\ce{H}\\
|\phantom{......}|\phantom{......}|\phantom{......}|\\
\ce{H - C - C - C - C - H}\\
|\phantom{......}|\phantom{......}|\phantom{......}|\\
\ce{H}\phantom{....}\ce{H}\phantom{....}\ce{H}\phantom{....}\ce{H}\\
\end{array}\]

shaalaa.com
Solution 2
n-butane:
CH3 - CH2 - CH2 - CH3
Iso-propane:
\[\begin{array}{cc}
\ce{CH3 - CH - CH3}\\
|\\
\ce{CH3}\\
\end{array}\]
shaalaa.com
Is there an error in this question or solution?
