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Draw two structural isomers of butane. - Science

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Draw two structural isomers of butane.

Draw structural isomers of butane (C4H10).

Chemical Equations/Structures
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Solution 1

The two isomers of butane, C4H10 are:

\[\begin{array}{cc}
\ce{H}\phantom{....}\ce{H}\phantom{....}\ce{H}\phantom{....}\ce{H}\\
|\phantom{......}|\phantom{......}|\phantom{......}|\\
\ce{H - C - C - C - C - H}\\
|\phantom{......}|\phantom{......}|\phantom{......}|\\
\ce{H}\phantom{....}\ce{H}\phantom{....}\ce{H}\phantom{....}\ce{H}\\
\end{array}\]

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Solution 2

n-butane:

CH3 - CH2 - CH2 - CH3

Iso-propane:

\[\begin{array}{cc}
\ce{CH3 - CH - CH3}\\
|\\
\ce{CH3}\\
\end{array}\]

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2022-2023 (March) Delhi Set 3
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