Question

Draw two structural isomers of butane.

Draw structural isomers of butane (C₄H₁₀).

Answer 1

The two isomers of butane, C₄H₁₀ are:

\[\begin{array}{cc}
\ce{H}\phantom{....}\ce{H}\phantom{....}\ce{H}\phantom{....}\ce{H}\\
|\phantom{......}|\phantom{......}|\phantom{......}|\\
\ce{H - C - C - C - C - H}\\
|\phantom{......}|\phantom{......}|\phantom{......}|\\
\ce{H}\phantom{....}\ce{H}\phantom{....}\ce{H}\phantom{....}\ce{H}\\
\end{array}\]

Answer 2

n-butane:

CH₃ – CH₂ – CH₂ – CH₃

Iso-propane:

\[\begin{array}{cc}
\ce{CH3 - CH - CH3}\\
|\phantom{...}\\
\ce{CH3}\\
\end{array}\]