Advertisements
Advertisements
Question
Draw a triangle PQR in which QR = 6 cm, PQ = 5 cm and times the corresponding sides of ΔPQR?
Advertisements
Solution
A ΔP'Q'R' whose sides are `3/5`of the corresponding sides of ΔPQR can be drawn as follows:
Step 1
Draw a ΔPQR with side QR = 6 cm, PQ = 5 cm and ∠PQR = 60°.
Step 2
Draw a ray QX making an acute angle with QR on the opposite side of vertex P.
Step 3
Locate 5 points (as 5 is greater in 3 and 5), Q1, Q2, Q3, Q4 and Q5 on line segment QX.
Step 4
Join Q5R and draw a line through Q3, parallel to Q5R intersecting QR at R'.
Step 5
Draw a line through R' parallel to PR intersecting PQ at P'.
Δ P'Q'R' is the required triangle.
APPEARS IN
RELATED QUESTIONS
A sum of Rs 700 is to be used to give seven cash prizes to students of a school for their overall academic performance. If each prize is Rs 20 less than its preceding prize, find the value of each of the prizes.
Find the 12th term from the end of the following arithmetic progressions:
3, 5, 7, 9, ... 201
Find the sum of n terms of an A.P. whose nth terms is given by an = 5 − 6n.
Which term of AP 72,68,64,60,… is 0?
The 4th term of an AP is 11. The sum of the 5th and 7th terms of this AP is 34. Find its common difference
How many terms of the AP 21, 18, 15, … must be added to get the sum 0?
The 9th term of an A.P. is 449 and 449th term is 9. The term which is equal to zero is
Write the formula of the sum of first n terms for an A.P.
If the first term of an AP is –5 and the common difference is 2, then the sum of the first 6 terms is ______.
Find the middle term of the AP. 95, 86, 77, ........, – 247.
