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Does the Expansion of ( 2 X 2 − 1 X ) Contain Any Term Involving X9?

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Question

Does the expansion of \[\left( 2 x^2 - \frac{1}{x} \right)\] contain any term involving x9?

 
 
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Solution

Suppose x9 occurs in the given expression at the (+ 1)th term.
Then, we have: 

\[T_{r + 1} =^{20}{}{C}_r (2 x^2 )^{20 - r} \left( \frac{- 1}{x} \right)^r \]
\[ = ( - 1 )^r   {20}{}{C}_r \left( 2 \right)^{20 - r} \left( x \right)^{40 - 2r - r} \]
\[\text{ For this term to contain }  x^9 , \text{ we must have} \]
\[40 - 3r = 9\]
\[ \Rightarrow 3r = 31\]
\[ \Rightarrow r = \frac{31}{3} \]
\[\text{ It is not possible, as r is not an integer } .\]

Hence, there is no term with x9 in the given expression.

 
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Introduction of Binomial Theorem
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Chapter 18: Binomial Theorem - Exercise 18.2 [Page 38]

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R.D. Sharma Mathematics [English] Class 11
Chapter 18 Binomial Theorem
Exercise 18.2 | Q 11 | Page 38

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