मराठी

Does the Expansion of ( 2 X 2 − 1 X ) Contain Any Term Involving X9? - Mathematics

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प्रश्न

Does the expansion of \[\left( 2 x^2 - \frac{1}{x} \right)\] contain any term involving x9?

 
 
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उत्तर

Suppose x9 occurs in the given expression at the (+ 1)th term.
Then, we have: 

\[T_{r + 1} =^{20}{}{C}_r (2 x^2 )^{20 - r} \left( \frac{- 1}{x} \right)^r \]
\[ = ( - 1 )^r   {20}{}{C}_r \left( 2 \right)^{20 - r} \left( x \right)^{40 - 2r - r} \]
\[\text{ For this term to contain }  x^9 , \text{ we must have} \]
\[40 - 3r = 9\]
\[ \Rightarrow 3r = 31\]
\[ \Rightarrow r = \frac{31}{3} \]
\[\text{ It is not possible, as r is not an integer } .\]

Hence, there is no term with x9 in the given expression.

 
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Introduction of Binomial Theorem
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 18: Binomial Theorem - Exercise 18.2 [पृष्ठ ३८]

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आरडी शर्मा Mathematics [English] Class 11
पाठ 18 Binomial Theorem
Exercise 18.2 | Q 11 | पृष्ठ ३८

संबंधित प्रश्‍न

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\[= ^{5}{}{C}_0 (2x )^5 (3y )^0 +^{5}{}{C}_1 (2x )^4 (3y )^1 + ^{5}{}{C}_2 (2x )^3 (3y )^2 + ^{5}{}{C}_3 (2x )^2 (3y )^3 + ^{5}{}{C}_4 (2x )^1 (3y )^4 +^{5}{}{C}_5 (2x )^0 (3y )^5\]

\[= 32 x^5 + 5 \times 16 x^4 \times 3y + 10 \times 8 x^3 \times 9 y^2 + 10 \times 4 x^2 \times 27 y^3 + 5 \times 2x \times 81 y^4 + 243 y^5 \]
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