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Maharashtra State BoardSSC (English Medium) 8th Standard

Divide. Write the quotient and the remainder. (25m4 − 15m3 + 10m + 8) ÷ 5m3 - Mathematics

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Question

Divide. Write the quotient and the remainder.

(25m4 − 15m3 + 10m + 8) ÷ 5m3

Sum
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Solution

(25m4 − 15m3 + 10m + 8) ÷ 5m3

= \[\frac{25 m^4 - 15 m^3 + 10m + 8}{5 m^3}\] 

= \[\frac{5 m^3 \left(5m - 3 \right) + \left(10m + 8 \right)}{5 m^3}\] 

= \[\frac{5 m^3 \left(5m - 3 \right)}{5 m^3} + \frac{\left(10m + 8 \right)}{5 m^3}\] 

= \[\left( 5m - 3 \right) + \frac{\left( 10m + 8 \right)}{5 m^3}\]

So, quotient = 5m - 3 and remainder = 10m + 8

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Chapter 10: Division of Polynomials - Practice Set 10.1 [Page 64]

APPEARS IN

Balbharati Mathematics [English] Standard 8 Maharashtra State Board
Chapter 10 Division of Polynomials
Practice Set 10.1 | Q 10 | Page 64
Balbharati Mathematics Integrated [English] Standard 8 Maharashtra State Board
Chapter 10 Division of Polynomials
Practice Set 10.1 | Q 1. (10) | Page 39
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