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Question
Divide the sum of `5/8` and `(-11)/12` by the difference of `3/7` and `5/14`.
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Solution
Sum of `5/8` and `(-11)/12 = 5/8 + ((-11)/12)`
`= 5/8 - 11/12`
`= ((5xx3) - (11xx2))/24`
(LCM of 8 and 12 is 24)
`= (15-22)/24 = (-7)/24`
Now, difference of `3/7` and `5/14`
`= ((3xx2)-(5xx1))/14 "or" (5-(3xx2))/14`
(LCM of 7 and 13 = 14)
`= (6-5)/14 "or" (5-6)/14 = 1/14 "or" (-1)/14`
Now, divide `(-7)/24 "by" 1/14 "or" (-1)/14`
`= ((-7)/24)/(1/14) "or" ((-7)/24)/((-1)/14)`
`= (-7)/24 xx 14/1 "or" (-7)/24 xx (-14)/1`
` = (-49)/12 "or" 49/12 = -4 1/12 "or" 4 1/12`
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