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Question
Differentiate the following:
F(x) = (x3 + 4x)7
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Solution
F(x) = (x3 + 4x)7
[y = f(g(x)
`("d"y)/("d"x)` = f'(g(x)) . g'(x)]
F'(x) = `7(x^3 + 4x)^(7 - 1) "d"/("d"x) (x^3 + 4x)`
= 7(x3 + 4x)6 (3x2 + 4)
= 7(3x2 + 4)(x3 + 4x)6
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