Question

Diagonal of a square is 20 cm. Find the length and perimeter of the square.

Answer 1

Diagonal of square = 20 cm.
Let side of square = x
∴ x² + x² = 20² ..................(By Pythagoras theorem)
∴ 2x² = 400

∴ x² = 200
∴ x = `10sqrt2 `cm.
Perimeter of square = 4 × `10sqrt2` =` 40sqrt2`
(i) Side of square =` 10sqrt2` cm.
(ii) Perimeter of square = `40sqrt2` cm.