Advertisements
Advertisements
Question
Determine the values of all the four quantum numbers of the 8th electron in the O-atom and 15th electron in Cl atom.
Advertisements
Solution
(1) O (Z = 8) 1s2 2s2 2px2 2py1 2pz1
Four quantum numbers for 2px1 electron in oxygen atom:
n = principal quantum number = 2
l = azimuthal quantum number = 1
m = magnetic quantum number = +1
s = spin quantum number = `+1/2`
(2) Cl (Z = 17) 1s2 2s2 2p6 3s2 3px2 3py2 3pz1
Four quantum numbers for 15th electron in chlorine atom:
n = 3, l = 1, m = 0, s = `+1/2`
(3) Cr (Z = 24) 1s2 2s2 2p2 3s2 3p2 3d2 4s1
n = 3, l = 2, m = +2, s = `+1/2`
APPEARS IN
RELATED QUESTIONS
Electronic configuration of species M2+ is 1s2 2s2 2p6 3s2 3p6 3d6 and its atomic weight is 56. The number of neutrons in the nucleus of species M is
The maximum number of electrons in a sub shell is given by the expression
If n = 6, the correct sequence for filling of electrons will be,
How many electrons in an atom with atomic number 105 can have (n + 1) = 8?
The energy of an electron in the 3rd orbit of hydrogen atom is –E. The energy of an electron in the first orbit will be
State and explain Pauli's exclusion principle.
Calculate the uncertainty in position of an electron, if Δv = 0.1% and υ = 2.2 × 106 ms-1
Describe the Aufbau principle.
An atom of an element contains 35 electrons and 45 neutrons. Deduce
- the number of protons
- the electronic configuration for the element
- All the four quantum numbers for the last electron
Calculate the energy required for the process.
\[\ce{He^+_{(g)} -> He^2+_{(g)} + e^-}\]
The ionisation energy for the H atom in its ground state is −13.6 ev atom−1.
