Advertisements
Advertisements
Question
Identify the missing quantum numbers and the sub energy level
| n | l | m | Sub energy level |
| ? | ? | 0 | 4d |
| 3 | 1 | 0 | ? |
| ? | ? | ? | 5p |
| ? | ? | −2 | 3d |
Advertisements
Solution
| n | l | m | Sub energy level |
| 4 | 2 | 0 | 4d |
| 3 | 1 | 0 | 3p |
| 5 | 1 | Anyone value (−1, 0, +1) |
5p |
| 3 | 2 | −2 | 3d |
APPEARS IN
RELATED QUESTIONS
Electronic configuration of species M2+ is 1s2 2s2 2p6 3s2 3p6 3d6 and its atomic weight is 56. The number of neutrons in the nucleus of species M is
Assertion: The spectrum of He+ is expected to be similar to that of hydrogen.
Reason: He+ is also one electron system.
The maximum number of electrons in a sub shell is given by the expression
If n = 6, the correct sequence for filling of electrons will be,
The energy of an electron in the 3rd orbit of hydrogen atom is –E. The energy of an electron in the first orbit will be
Consider the following electronic arrangements for the d5 configuration.
| ⥮ | ⥮ | 1 | ||
| (a) | ||||
| 1 | 1 | 1 | ⥮ | |
| (b) | ||||
| 1 | 1 | 1 | 1 | 1 |
| (c) | ||||
- which of these represents the ground state.
- which configuration has the maximum exchange energy.
Define orbital?
Calculate the uncertainty in position of an electron, if Δv = 0.1% and υ = 2.2 × 106 ms-1
For each of the following, give the sub level designation, the allowable m values and the number of orbitals
- n = 4, l = 2
- n = 5, l = 3
- n = 7, l = 0
An atom of an element contains 35 electrons and 45 neutrons. Deduce
- the number of protons
- the electronic configuration for the element
- All the four quantum numbers for the last electron
