Advertisements
Advertisements
Question
The electronic configuration of Eu (Atomic no. 63) Gd (Atomic no. 64) and Tb (Atomic no. 65) are:
Options
[Xe] 4f6 5d1 6s2, [Xe] 4f7 5d1 6s2 and [Xe] 4f8 5d1 6s2
[Xe] 4f7 6s2, [Xe] 4f7 5d1 6s2 and [Xe] 4f9 6s2
[Xe] 4f7 6s2, [Xe] 4f8 6s2 and [Xe] 4f8 5d1 6s2
[Xe] 4f6 5d1 6s2, [Xe] 4f7 5d1 6s2 and [Xe] 4f9 6s2
Advertisements
Solution
[Xe] 4f7 6s2, [Xe] 4f7 5d1 6s2 and [Xe] 4f9 6s2
RELATED QUESTIONS
Electronic configuration of species M2+ is 1s2 2s2 2p6 3s2 3p6 3d6 and its atomic weight is 56. The number of neutrons in the nucleus of species M is
Assertion: The spectrum of He+ is expected to be similar to that of hydrogen.
Reason: He+ is also one electron system.
The maximum number of electrons in a sub shell is given by the expression
If n = 6, the correct sequence for filling of electrons will be,
How many electrons in an atom with atomic number 105 can have (n + 1) = 8?
Consider the following electronic arrangements for the d5 configuration.
| ⥮ | ⥮ | 1 | ||
| (a) | ||||
| 1 | 1 | 1 | ⥮ | |
| (b) | ||||
| 1 | 1 | 1 | 1 | 1 |
| (c) | ||||
- which of these represents the ground state.
- which configuration has the maximum exchange energy.
For each of the following, give the sub level designation, the allowable m values and the number of orbitals
- n = 4, l = 2
- n = 5, l = 3
- n = 7, l = 0
Calculate the energy required for the process.
\[\ce{He^+_{(g)} -> He^2+_{(g)} + e^-}\]
The ionisation energy for the H atom in its ground state is −13.6 ev atom−1.
An ion with mass number 37 possesses unit negative charge. If the ion contains 11.1% more neutrons than electrons. Find the symbol of the ion.
Identify the missing quantum numbers and the sub energy level
| n | l | m | Sub energy level |
| ? | ? | 0 | 4d |
| 3 | 1 | 0 | ? |
| ? | ? | ? | 5p |
| ? | ? | −2 | 3d |
