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Question
Determine the order and degree (if defined) of the differential equation:
y″ + 2y′ + sin y = 0
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Solution
y″ + 2y′ + sin y = 0
The highest-order derivative present in the differential equation is y″.
Therefore, its order is two.
This is a polynomial equation in y″ and y' and the highest power raised to y' is one.
Hence, its degree is one.
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