Advertisements
Advertisements
Question
cot θ . tan θ = ?
Options
1
0
2
`sqrt(2)`
Advertisements
Solution
1
Explanation:
`cot θ . tan θ = 1/(tan θ) . tan θ`
= 1
APPEARS IN
RELATED QUESTIONS
Express the ratios cos A, tan A and sec A in terms of sin A.
Prove the following trigonometric identities.
`(1 + tan^2 A) + (1 + 1/tan^2 A) = 1/(sin^2 A - sin^4 A)`
Prove the following trigonometric identities.
(sec A + tan A − 1) (sec A − tan A + 1) = 2 tan A
Prove that:
`(tanA + 1/cosA)^2 + (tanA - 1/cosA)^2 = 2((1 + sin^2A)/(1 - sin^2A))`
`(1-tan^2 theta)/(cot^2-1) = tan^2 theta`
Show that none of the following is an identity:
`tan^2 theta + sin theta = cos^2 theta`
Prove that `( sintheta - 2 sin ^3 theta ) = ( 2 cos ^3 theta - cos theta) tan theta`
`If sin theta = cos( theta - 45° ),where theta " is acute, find the value of "theta` .
If `secθ = 25/7 ` then find tanθ.
Prove the following identity :
`(cosecA)/(cosecA - 1) + (cosecA)/(cosecA + 1) = 2sec^2A`
Prove the following identity :
`sqrt((secq - 1)/(secq + 1)) + sqrt((secq + 1)/(secq - 1))` = 2 cosesq
Prove the following identity :
`(1 + tan^2θ)sinθcosθ = tanθ`
If sec θ = x + `1/(4"x"), x ≠ 0,` find (sec θ + tan θ)
Prove that sin2 θ + cos4 θ = cos2 θ + sin4 θ.
If x = a sec θ + b tan θ and y = a tan θ + b sec θ prove that x2 - y2 = a2 - b2.
sec2θ – tan2θ = ?
Prove that 2(sin6A + cos6A) – 3(sin4A + cos4A) + 1 = 0.
If 2sin2β − cos2β = 2, then β is ______.
Prove that (sec θ + tan θ) (1 – sin θ) = cos θ
