Advertisements
Advertisements
प्रश्न
cot θ . tan θ = ?
पर्याय
1
0
2
`sqrt(2)`
Advertisements
उत्तर
1
Explanation:
`cot θ . tan θ = 1/(tan θ) . tan θ`
= 1
APPEARS IN
संबंधित प्रश्न
If cosθ + sinθ = √2 cosθ, show that cosθ – sinθ = √2 sinθ.
Prove the following trigonometric identities.
`tan theta + 1/tan theta` = sec θ.cosec θ
Prove the following trigonometric identities.
`(cosec A)/(cosec A - 1) + (cosec A)/(cosec A = 1) = 2 sec^2 A`
If x = a sec θ cos ϕ, y = b sec θ sin ϕ and z = c tan θ, show that `x^2/a^2 + y^2/b^2 - x^2/c^2 = 1`
Prove the following identities:
(1 – tan A)2 + (1 + tan A)2 = 2 sec2A
Prove the following identities:
`(cosecA)/(cosecA - 1) + (cosecA)/(cosecA + 1) = 2sec^2A`
Prove the following identities:
`cotA/(1 - tanA) + tanA/(1 - cotA) = 1 + tanA + cotA`
If x= a sec `theta + b tan theta and y = a tan theta + b sec theta ,"prove that" (x^2 - y^2 )=(a^2 -b^2)`
Write the value of `sin theta cos ( 90° - theta )+ cos theta sin ( 90° - theta )`.
If `cos theta = 7/25 , "write the value of" ( tan theta + cot theta).`
Find the value of sin ` 48° sec 42° + cos 48° cosec 42°`
What is the value of \[\sin^2 \theta + \frac{1}{1 + \tan^2 \theta}\]
If sec θ + tan θ = x, then sec θ =
Prove the following identity :
`(tanθ + secθ - 1)/(tanθ - secθ + 1) = (1 + sinθ)/(cosθ)`
Without using trigonometric identity , show that :
`tan10^circ tan20^circ tan30^circ tan70^circ tan80^circ = 1/sqrt(3)`
Prove that : `1 - (cos^2 θ)/(1 + sin θ) = sin θ`.
Prove that `sqrt((1 + sin θ)/(1 - sin θ))` = sec θ + tan θ.
Prove that `(sin θ. cos (90° - θ) cos θ)/sin( 90° - θ) + (cos θ sin (90° - θ) sin θ)/(cos(90° - θ)) = 1`.
a cot θ + b cosec θ = p and b cot θ + a cosec θ = q then p2 – q2 is equal to
If 1 + sin2α = 3 sinα cosα, then values of cot α are ______.
