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Question
`(cos 28°)/(sin 62°)` = ?
Options
2
-1
0
1
MCQ
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Solution
1
Explanation:
`[cos 28°]/[sin 62°]`
= `[sin( 90°- 28°)]/(sin 62°)` ...[cos θ = sin(90°- θ)]
= `[sin 62°]/[sin 62°]`
= 1
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Chapter 8: Trigonometry - Problem Set 8 [Page 113]
