Question

`(cos 28°)/(sin 62°)` = ?

विकल्प

• 2

• -1

• 0

• 1

Answer 1

1

Explanation:

`[cos 28°]/[sin 62°]`

= `[sin( 90°- 28°)]/(sin 62°)`     ...[cos θ = sin(90°- θ)]

= `[sin 62°]/[sin 62°]`   

= 1