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Question
`(cos^2 30^circ cos^2 45^circ + 4 sec^2 60^circ + 1/2 cos^2 90^circ - 2 tan^2 60^circ)` = ?
Options
`81/8`
`83/8`
`73/8`
`75/8`
MCQ
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Solution
`bb(83/8)`
Explanation:
Given expression = `{(sqrt(3)/2)^2 xx (1/sqrt(2))^2 + (4 xx 2^2) + (1/2 xx 0^2) - 2 xx (sqrt(3))^2}`
= `{(3/4 xx 1/2) + 16 + 0 - 6}`
= `(3/8 + 10)`
= `83/8`
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