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(3 cos^260° + 2 cot^230° – 5 sin^245°) = ?

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Question

(3 cos260° + 2 cot230° – 5 sin245°) = ?

Options

  • 1

  • 4

  • `17/4`

  • `13/6`

MCQ
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Solution

`bb(17/4)`

Explanation:

Given expression = `{3 xx (1/2)^2 + 2 xx (sqrt(3))^2 - 5 xx (1/sqrt(2))^2}`

= `(3/4 + 6 - 5/2)`

= `17/4`

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Chapter 11: T-Ratios of Some Particular Angles - MULTIPLE-CHOICE QUESTIONS (MCQ) [Page 576]

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R.S. Aggarwal Mathematics [English] Class 10
Chapter 11 T-Ratios of Some Particular Angles
MULTIPLE-CHOICE QUESTIONS (MCQ) | Q 3. | Page 576
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