Question

Construct an isosceles triangle PQR where PQ = PR and ∠Q = 50°, QR = 7 cm. Also draw its circumcircle.

Answer 1

Given PQ = PR

∴ ∠R = 50° ...(opposite angles are equal)

Steps for construction:

Step 1: Draw the ΔABC with the given measures.

Step 2: Construct the perpendicular bisector of any two sides (QR and PR) and let them meet at S. S is the circumcenter of ΔPQR.

Step 3: With S as centre SP = SQ = SR as radius. Draw the circumcircle.

Circum radius = 3.5 cm.