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प्रश्न
Construct an isosceles triangle PQR where PQ = PR and ∠Q = 50°, QR = 7 cm. Also draw its circumcircle.
आकृती
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उत्तर
Given PQ = PR
∴ ∠R = 50° ...(opposite angles are equal)
Steps for construction:
Step 1: Draw the ΔABC with the given measures.
Step 2: Construct the perpendicular bisector of any two sides (QR and PR) and let them meet at S. S is the circumcenter of ΔPQR.
Step 3: With S as centre SP = SQ = SR as radius. Draw the circumcircle.
Circum radius = 3.5 cm.
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