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Question
Complete the following reaction:
\[\ce{(C6H5CH2)2Cd + 2CH3COCI}\]
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Solution
Treatment of acyl chlorides with dialkylcadmium gives a ketone.
\[\ce{2 CH3 - CO - CI + (C6H5- CH2)2 Cd -> \underset{\text{1-Phenylpropan-2-one}}{2 CH3-CO-CH2-C6H5} + CdCI2}\]
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