Advertisements
Advertisements
प्रश्न
Complete the following reaction:
\[\ce{(C6H5CH2)2Cd + 2CH3COCI}\]
Advertisements
उत्तर
Treatment of acyl chlorides with dialkylcadmium gives a ketone.
\[\ce{2 CH3 - CO - CI + (C6H5- CH2)2 Cd -> \underset{\text{1-Phenylpropan-2-one}}{2 CH3-CO-CH2-C6H5} + CdCI2}\]
APPEARS IN
संबंधित प्रश्न
Write the IUPAC name of the follow
\[\begin{array}\ce{\phantom{--..}O}\\\ce{\phantom{--..}||}\\ \ce{CH2=CH-C-CH3}\end{array}\]
What is the action of following reagents on ethanoic acid?
P2O5/heat
Write a reaction for the following conversion.
Benzene to Benzaldehyde.
In the formation of an aldol, α-carbon atom of one aldehyde molecule attaches to ____________ of another aldehyde molecule.
An acylchloride is hydrogenated over catalyst palladium on barium sulphate to form an aldehyde. This reaction is called as ______.
Which of the following is called as mandelonitrile?
The product of the reaction between dimethylcadmium and acetyl chloride is ____________.
Which among the following compound on treatment with DIBAL-H yields dodecanal at 195 K?
Given below are two statements labelled as Assertion (A) and Reason (R).
Assertion (A): SO2 is reducing while TeO2 is an oxidising agent.
Reason (R): Reducing property of dioxide decreases from SO2 to TeO2.
Select the most appropriate answer from the options given below:
The reaction
