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प्रश्न
Complete the following reaction:
\[\ce{(C6H5CH2)2Cd + 2CH3COCI}\]
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उत्तर
Treatment of acyl chlorides with dialkylcadmium gives a ketone.
\[\ce{2 CH3 - CO - CI + (C6H5- CH2)2 Cd -> \underset{\text{1-Phenylpropan-2-one}}{2 CH3-CO-CH2-C6H5} + CdCI2}\]
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\[\begin{array}{cc}
\phantom{...........}\ce{O}\\
\phantom{...........}||\\
\ce{2A + (C6H5CH2)2 Cd -> 2CH3 - C - CH2 - C6H5 + CdCl2}\end{array}\]
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