Advertisements
Advertisements
Question
Complete the following calculations. Show working for complete credit :
Calculate the mass of calcium that will contain the same number of atoms as are present in 3.2 gm of Sulphur. [Atomic masses : S = 32, Ca = 40]
Advertisements
Solution
3.2g of S has number of atoms = 6.023 × 1023 x 3.2 /32
= 0.6023 × 1023
So, 0.6023 × 1023 atoms of Ca has mass
= 40 × 0.6023 ×1023/6.023 × 1023 = 4g
APPEARS IN
RELATED QUESTIONS
The percentage composition of a gas is Nitrogen 82.35%, Hydrogen 17.64%. Find the empirical formula of the gas. [N = 14, H = 1]
The relative atomic mass of Cl atom is 35.5 a.m.u. Explain this statement.
The equation for the burning of octane is:
\[\ce{2C8H18 + 25O2 -> 16CO2 + 18H2O}\]
How many moles of carbon dioxide are produced when one mole of octane burns?
Which of the following would weight the least?
[Atomic masses : Ag = 108, N - 14, O = 16,C = 12]
Explain the term:
Molar volume
Calculate the number of particles in 0.1 mole of any substance.
Calculate the mass of 0.1 mole of the following:
Na2SO4.10H2O
(Ca = 40, Na = 23, Mg = 24, S = 32, C = 12, Cl = 35.5, O = 16, H = 1)
N2 + 3H2 → 2NH3
(The atomic mass of nitrogen is 14, and that of hydrogen is 1)
1 mole of nitrogen (______ g) +
3 moles of hydrogen (______ g) →
2 moles of ammonia (______ g)
Deduce the number of molecules of the following compound in the given quantity.
90g water
Deduce the number of molecules of the following compound in the given quantity.
8.8g carbon dioxide
