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Chords AC and BD intersect each other at point P. Assertion (A): PA × PC = PВ × PD Reason (R): Δ APD ∼ Δ BPC (PA)/(PB) = (PD)/(PC)

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Question

Chords AC and BD intersect each other at point P.

A circle with chords AC and BD intersecting at an interior point P.

Assertion (A): PA × PC = PВ × PD

Reason (R): Δ APD ∼ Δ BPC

A circle with chords AC and BD intersecting at P and angle markers at the circumference.

`(PA)/(PB) = (PD)/(PC)`

Options

  • A is true, R is false.

  • A is false, R is true.

  • Both A and R are true and R is the correct reason for A.

  • Both A and R are true and R is the incorrect reason for A .

MCQ
Assertion and Reasoning
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Solution

Both A and R are true and R is the correct reason for A.

Explanation:

In Δ APD and Δ BPC,

⇒ ∠APD = ∠BPC (Vertically opposite angles are equal)

⇒ ∠ADP = ∠BCP (Angles in same segment are equal)

∴ Δ APD ∼ Δ BPC (By A.A. similarity)

Corresponding sides of similar triangles are proportional.

⇒ `(AP)/(PB) = (PD)/(PC)`        ....(1)

So, reason (R) is true.

Solving (1),

⇒ AP × PC = PD × PB

So, assertion (A) is true and R is the correct reason for A.

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Chapter 17: Circles - TEST YOURSELF [Page 272]

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Selina Concise Mathematics [English] Class 10 ICSE
Chapter 17 Circles
TEST YOURSELF | Q 1. (j) | Page 272
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