मराठी

Chords AC and BD intersect each other at point P. Assertion (A): PA × PC = PВ × PD Reason (R): Δ APD ∼ Δ BPC (PA)/(PB) = (PD)/(PC)

Advertisements
Advertisements

प्रश्न

Chords AC and BD intersect each other at point P.

A circle with chords AC and BD intersecting at an interior point P.

Assertion (A): PA × PC = PВ × PD

Reason (R): Δ APD ∼ Δ BPC

A circle with chords AC and BD intersecting at P and angle markers at the circumference.

`(PA)/(PB) = (PD)/(PC)`

पर्याय

  • A is true, R is false.

  • A is false, R is true.

  • Both A and R are true and R is the correct reason for A.

  • Both A and R are true and R is the incorrect reason for A .

MCQ
विधान आणि तर्क
Advertisements

उत्तर

Both A and R are true and R is the correct reason for A.

Explanation:

In Δ APD and Δ BPC,

⇒ ∠APD = ∠BPC (Vertically opposite angles are equal)

⇒ ∠ADP = ∠BCP (Angles in same segment are equal)

∴ Δ APD ∼ Δ BPC (By A.A. similarity)

Corresponding sides of similar triangles are proportional.

⇒ `(AP)/(PB) = (PD)/(PC)`        ....(1)

So, reason (R) is true.

Solving (1),

⇒ AP × PC = PD × PB

So, assertion (A) is true and R is the correct reason for A.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 17: Circles - TEST YOURSELF [पृष्ठ २७२]

APPEARS IN

सेलिना Concise Mathematics [English] Class 10 ICSE
पाठ 17 Circles
TEST YOURSELF | Q 1. (j) | पृष्ठ २७२
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×