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Choose the correct option from the given alternatives: The mean and the variance of a binomial distribution are 4 and 2 respectively. Then the probablity of 2 successes is

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Question

Choose the correct option from the given alternatives:

The mean and the variance of a binomial distribution are 4 and 2 respectively. Then the probability of 2 successes is

Options

  • `128/256`

  • `219/256`

  • `37/256`

  • `28/256`

MCQ
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Solution

`28/256`

Explanation:

np = 4, npq = 2

∴ q = `1/2` and p = `1/2`

∴ `"n"(1/2) = 4`

∴ n = 8

∴ P(X = 2) = `"^8C_2 (1/2)^8 = (8 xx 7)/(1 xx 2) xx 1/256 = 28/256`

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Chapter 8: Binomial Distribution - Miscellaneous exercise 1 [Page 253]

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Balbharati Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
Chapter 8 Binomial Distribution
Miscellaneous exercise 1 | Q 2 | Page 253

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