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Choose the correct option from the given alternatives : ∫0π2sin2x⋅dx(1+cosx)2 = ______.

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Question

Choose the correct option from the given alternatives : 

`int_0^(pi/2) (sin^2x*dx)/(1 + cosx)^2` = ______.

Options

  • `(4 - pi)/2`

  • `(pi - 4)/2`

  • `4 - pi/(2)`

  • `(4 + pi)/2`

MCQ
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Solution

`int_0^(pi/2) (sin^2x*dx)/(1 + cosx)^2` = `bb(underline((4 - pi)/2))`.

Explanation:

`int_0^(pi/2) (sin^2x*dx)/(1 + cosx)^2 = int_0^(pi/2) (1- cos^2x)/(1 + cosx)^2dx` 

=  `int_0^(pi/2) ((1 + cosx)(1-cosx))/(1 + cosx)^2dx` 

=  `int_0^(pi/2) (1-cosx)/(1+cosx)dx` 

= `int_0^(pi/2) (2sin^2  x/2)/(2cos^2  x/2)dx`

= `int_0^(pi/2)tan^2  x/2dx`

= `int_0^(pi/2) (sec^2  x/2-1)dx`

= `(tan  x/2)/(1/2) - x`

= `2[tan  x/2-x]_0^(pi/2)`

= `2[tan  pi/4-pi/2]`

= `2 - pi/2`

= `(4-pi)/2`

shaalaa.com
Methods of Evaluation and Properties of Definite Integral
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Chapter 4: Definite Integration - Miscellaneous Exercise 4 [Page 175]

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