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Question
Calculate the total resistance across AB:
Numerical
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Solution
Given: \(R_1=3\,\Omega\)
\(R_2=6\,\Omega\)
\(R_3=5\,\Omega\)
The 3 Ω and 6 Ω resistors are connected in parallel.
\[ R_p=\frac{3\times6}{3+6}\]
\[=\frac{18}{9}\]
\[=2\,\Omega \]
This combination is connected in series with the 5 Ω resistor.
\[ R=2+5\]
\[=7\,\Omega\]
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