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Question
Calculate the number of water molecules present in one drop of water which weighs 0.18 g.
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Solution
One mole of water weighs 18 g.
18 g of water contains 6.023 × 1023 water molecules.
∴ 0.18 g of water contains
= `(6.023×10^23)/18` × 0.18
= 6.023 × 1021 water molecules.
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