Advertisements
Advertisements
प्रश्न
Calculate the number of water molecules present in one drop of water which weighs 0.18 g.
Advertisements
उत्तर
One mole of water weighs 18 g.
18 g of water contains 6.023 × 1023 water molecules.
∴ 0.18 g of water contains
= `(6.023×10^23)/18` × 0.18
= 6.023 × 1021 water molecules.
APPEARS IN
संबंधित प्रश्न
Write the molecular formulae of Nitric acide :
The valency of sodium is one, write the molecular formula for sodium oxide ?
How many units of charge are developed on each atom?
‘Atoms of the same element or different from Dalton’s atomic theory by the Modern Atomic Theory.
Give two examples each of –
- Atoms of the same element
- Atoms of different elements combining to form a molecule.
State the correct formula of the following from the option given:
Sodium bisulphite
State the correct formula of the following from the option given:
Ammonium sulphate
State the correct formula of the following from the option given:
Copper [II] nitrate
What is the fraction of the mass of water due to neutrons?
Compute the number of ions present in 5.85 g of sodium chloride
A molecule that contains only one atom is called ______ molecule.
