Advertisements
Advertisements
प्रश्न
Calculate the number of water molecules present in one drop of water which weighs 0.18 g.
Advertisements
उत्तर
One mole of water weighs 18 g.
18 g of water contains 6.023 × 1023 water molecules.
∴ 0.18 g of water contains
= `(6.023×10^23)/18` × 0.18
= 6.023 × 1021 water molecules.
APPEARS IN
संबंधित प्रश्न
Write the molecular formulae of Sodiun sulphide:
Write the molecular formulae of Nitric acide :
Write the molecular formulae of Aluminium sulphate :
The valency of sodium is one, write the molecular formula for sodium nitratev ?
In hydrogen peroxide (H2O2), the proportion of hydrogen and oxygen by mass is :
What is the number of electrons donated by a magnesium atom and number of electrons accepted by a sulphur atom during their chemical combination?
Diagrammatically represent the transfer of electrons.
State the correct formula of the following from the option given:
Ammonium sulphate
Express each of the following in kilograms
0.584 g
A group of atoms carrying a fixed charge on them is called ————.
