Advertisements
Advertisements
Question
By using identity evaluate the following:
`1 + 1/8 - 27/8`
Advertisements
Solution
We know that a3 + b3 + c3 = 0 then a + b + c = 3abc
`1 + 1/8 - 27/8 = 1^3 + (1/2)^3 - (3/2)^3`
a + b + c = `1 + 1/2 - 3/2`
= `(2 + 1 - 3)/2`
= `0/2`
= 0
`1 + 1/8 - 27/8 = 3(1) xx 1/2 xx ((-3)/2)`
= `(-9)/4`
APPEARS IN
RELATED QUESTIONS
Show that `(4pq + 3q)^2 - (4pq - 3q)^2 = 48pq^2`
Simplify the following using the identities: \[\frac{{58}^2 - {42}^2}{16}\]
Evaluate the following: 102 × 106
Simplify:
(3x + 2y)2 – (3x – 2y)2
Simplify:
(ab – c)2 + 2abc
Simplify:
(a – b) (a2 + b2 + ab) – (a + b) (a2 + b2 – ab)
Expand the following, using suitable identities.
(2x + 9)(2x – 7)
Expand the following, using suitable identities.
(7x + 5)2
Using suitable identities, evaluate the following.
(49)2
Using suitable identities, evaluate the following.
52 × 53
