Advertisements
Advertisements
प्रश्न
By using identity evaluate the following:
`1 + 1/8 - 27/8`
Advertisements
उत्तर
We know that a3 + b3 + c3 = 0 then a + b + c = 3abc
`1 + 1/8 - 27/8 = 1^3 + (1/2)^3 - (3/2)^3`
a + b + c = `1 + 1/2 - 3/2`
= `(2 + 1 - 3)/2`
= `0/2`
= 0
`1 + 1/8 - 27/8 = 3(1) xx 1/2 xx ((-3)/2)`
= `(-9)/4`
APPEARS IN
संबंधित प्रश्न
Show that `(4pq + 3q)^2 - (4pq - 3q)^2 = 48pq^2`
Simplify the following using the formula: (a − b)(a + b) = a2 − b2: (82)2 − (18)2
Simplify the following using the formula: (a − b)(a + b) = a2 − b2: 9.8 × 10.2
Find the following product: (3x − 4y) (2x − 4y)
Find the following product: (3x2 − 4xy) (3x2 − 3xy)
Simplify:
(4.5a + 1.5b)2 + (4.5b + 1.5a)2
Expand the following, using suitable identities.
(2x + 9)(2x – 7)
Expand the following, using suitable identities.
(x2 + y2)(x2 – y2)
Expand the following, using suitable identities.
(7x + 5)2
Carry out the following division:
76x3yz3 ÷ 19x2y2
