Advertisements
Advertisements
प्रश्न
By using identity evaluate the following:
`1 + 1/8 - 27/8`
Advertisements
उत्तर
We know that a3 + b3 + c3 = 0 then a + b + c = 3abc
`1 + 1/8 - 27/8 = 1^3 + (1/2)^3 - (3/2)^3`
a + b + c = `1 + 1/2 - 3/2`
= `(2 + 1 - 3)/2`
= `0/2`
= 0
`1 + 1/8 - 27/8 = 3(1) xx 1/2 xx ((-3)/2)`
= `(-9)/4`
APPEARS IN
संबंधित प्रश्न
Simplify the following using the formula: (a − b)(a + b) = a2 − b2: (82)2 − (18)2
Find the following product: (x + 7) (x − 5)
Find the following product: \[\left( x + \frac{4}{3} \right)\left( x + \frac{3}{4} \right)\]
Find the following product: \[\left( z + \frac{3}{4} \right)\left( z + \frac{4}{3} \right)\]
Find the following product: (p2 + 16) \[\left( p^2 - \frac{1}{4} \right)\]
Using algebraic identity, find the coefficients of x2, x and constant term without actual expansion
(x + 5)(x + 6)(x + 7)
Evaluate the following by using identities:
983
Expand the following, using suitable identities.
`(4/5a + 5/4b)^2`
Expand the following, using suitable identities.
`(4/5p + 5/3q)^2`
Expand the following, using suitable identities.
(0.9p – 0.5q)2
